# Ex 6.3,4 - Chapter 6 Class 12 Application of Derivatives (Term 1)

Last updated at April 14, 2021 by Teachoo

Last updated at April 14, 2021 by Teachoo

Transcript

Ex 6.3, 4 Find the slope of the tangent to the curve π¦=π₯^3β3π₯+2 at the point whose π₯βcoordinate is 3 π¦=π₯^3β3π₯+2 We know that slope of tangent =ππ¦/ππ₯ ππ¦/ππ₯=3π₯^2β3 Since π₯βcoordinate is 3 Putting π₯=3 in (1) γππ¦/ππ₯βγ_(π₯ = 3)=3(3)^2β3 =3 Γ9β3 =27β3 =24 Hence slope of tangent is 24

Ex 6.3

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Ex 6.3,4 You are here

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Ex 6.3, 14 (i)

Ex 6.3, 14 (ii) Important

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Ex 6.3,26 (MCQ) Important

Ex 6.3,27 (MCQ)

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